Source Code : Init Param Servlet

Java Is Open Source Programming Language You Can Download From Java and Java Libraries From http://www.oracle.com. Click Here to download
We provide this code related to title for you to solve your developing problem easily. Libraries which is import in this program you can download from http://www.oracle.com. Click Here or search from google with Libraries Name you get jar file related it

Init Param Servlet

  

import javax.servlet.ServletConfig;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import java.io.PrintWriter;
import java.io.IOException;

public class InitParamServlet extends HttpServlet 
{
  public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException, ServletException 
  {

    res.setContentType("text/plain");
    PrintWriter out = res.getWriter();

    String url = getInitParameter("URL");

    ServletConfig config = getServletConfig();
    ServletContext context = getServletContext();
    String uid = config.getInitParameter("UID");
    String pwd = config.getInitParameter("PWD");
    String port = context.getInitParameter("some-port");

    out.println("Values retrieved for the init parameters are: ");
    out.println("URL: " + url);
    out.println("UID: " + uid);
    out.println("PWD: " + pwd);
    out.println("some-port: " + port);
  }
}

           
         
    
  

Thank with us